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CuSO 4 ( aq. ) → H 2 S ↑ M ↓ → Excess of KCN N + O \text{CuSO}_4(\text{aq.}) \xrightarrow{\text{H}_2\text{S} \uparrow} \text{M} \downarrow \xrightarrow{\text{Excess of KCN}} \text{N} + \text{O} CuSO 4 ( aq. ) H 2 S ↑ M ↓ Excess of KCN N + O …
Problem CuSO 4 ( aq. ) → H 2 S ↑ M ↓ → Excess of KCN N + O \text{CuSO}_4(\text{aq.}) \xrightarrow{\text{H}_2\text{S} \uparrow} \text{M} \downarrow \xrightarrow{\text{Excess of KCN}} \text{N} + \text{O} CuSO 4 ( aq. ) H 2 S ↑ M ↓ Excess of KCN N + O
Then final products N and O are respectively.
a. [Cu(CN)4 ]3- , (CN)2
b. CuCN, (CN)2
c. [Cu(CN)4 ]2- , (CN)2
d. Cu(CN)2 , K2 S
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