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Chemistry
Chemistry
Problem
The correct order of decreasing ionic nature of lead dihalides is: a.
PbF
2
>
PbCl
2
>
PbBr
2
>
PbI
2
\text{PbF}_2 > \text{PbCl}_2 > \text{PbBr}_2 > \text{PbI}_2
PbF
2
>
PbCl
2
>
PbBr
2
>
PbI
2
b.
PbF
2
>
PbBr
2
>
PbCl
2
>
PbI
2
\text{PbF}_2 > \text{PbBr}_2 > \text{PbCl}_2 > \text{PbI}_2
PbF
2
>
PbBr
2
>
PbCl
2
>
PbI
2
c.
PbF
2
<
PbCl
2
>
PbBr
2
<
PbI
2
\text{PbF}_2 < \text{PbCl}_2 > \text{PbBr}_2 < \text{PbI}_2
PbF
2
<
PbCl
2
>
PbBr
2
<
PbI
2
d.
PbI
2
<
PbBr
2
<
PbCl
2
<
PbF
2
\text{PbI}_2 < \text{PbBr}_2 < \text{PbCl}_2 < \text{PbF}_2
PbI
2
<
PbBr
2
<
PbCl
2
<
PbF
2
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