Mathematics

Mathematics

Problem

Prove that 122sec⁡2x2+124sec⁡2x22+126sec⁡2x23+…∞=csc⁡2x−1x2\frac{1}{2^2} \sec^2 \frac{x}{2} + \frac{1}{2^4} \sec^2 \frac{x}{2^2} + \frac{1}{2^6} \sec^2 \frac{x}{2^3} + \dots \infty = \csc^2 x - \frac{1}{x^2}.

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