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Mathematics
Mathematics
Problem
Area of quadrilateral formed with the foci of the hyperbola
x
2
a
2
−
y
2
b
2
=
1
\frac{x^2}{a^2} - \frac{y^2}{b^2} = 1
a
2
x
2
−
b
2
y
2
=
1
and
x
2
a
2
−
y
2
b
2
=
−
1
\frac{x^2}{a^2} - \frac{y^2}{b^2} = -1
a
2
x
2
−
b
2
y
2
=
−
1
is a.
4
(
a
2
+
b
2
)
4(a^2 + b^2)
4
(
a
2
+
b
2
)
b.
2
(
a
2
+
b
2
)
2(a^2 + b^2)
2
(
a
2
+
b
2
)
c.
(
a
2
+
b
2
)
(a^2 + b^2)
(
a
2
+
b
2
)
d.
1
2
(
a
2
+
b
2
)
\frac{1}{2}(a^2 + b^2)
2
1
(
a
2
+
b
2
)
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