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Problem
Problem
If
k
=
∑
n
=
1
∞
6
n
(
3
n
−
2
n
)
(
3
n
+
1
−
2
n
+
1
)
k = \sum_{n=1}^{\infty} \frac{6^n}{(3^n - 2^n)(3^{n+1} - 2^{n+1})}
k
=
∑
n
=
1
∞
(
3
n
−
2
n
)
(
3
n
+
1
−
2
n
+
1
)
6
n
, the value of
k
k
k
is .....
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