Physics

Physics

Problem

The relation between [ϵ0][\epsilon_0] and [μ0][\mu_0] is a. [μ0]=[ϵ0][L]2[T]−2[\mu_0] = [\epsilon_0] [L]^2 [T]^{-2} b. [μ0]=[ϵ0][L]−2[T]2[\mu_0] = [\epsilon_0] [L]^{-2} [T]^2 c. [μ0]=[ϵ0]−1[L]2[T]−2[\mu_0] = [\epsilon_0]^{-1} [L]^2 [T]^{-2} d. [μ0]=[ϵ0]−1[L]−2[T]2[\mu_0] = [\epsilon_0]^{-1} [L]^{-2} [T]^2

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