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Mathematics
Mathematics
Problem
If
sin
θ
=
cos
θ
\sin \theta = \cos \theta
sin
θ
=
cos
θ
,
(
0
∘
<
θ
<
90
∘
)
(0^\circ < \theta < 90^\circ)
(
0
∘
<
θ
<
9
0
∘
)
, then value of
(
sec
θ
⋅
sin
θ
)
(\sec \theta \cdot \sin \theta)
(
sec
θ
⋅
sin
θ
)
is : (CBSE 2024) (1)
1
2
\frac{1}{\sqrt{2}}
2
1
(2)
2
\sqrt{2}
2
(3) 1 (4) 0
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