Mathematics

Mathematics

Problem

If PP is a point on the circle x2+y2=9x^2 + y^2 = 9, QQ is a point on the line 7x+y+3=07x + y + 3 = 0, and the line x−y+1=0x - y + 1 = 0, is the perpendicular bisector of PQPQ, then the coordinates of PP are a. (3,0)(3, 0) b. (7225,−2125)\left(\frac{72}{25}, -\frac{21}{25}\right) c. (0,3)(0, 3) d. (−7225,2125)\left(-\frac{72}{25}, \frac{21}{25}\right)

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