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Mathematics
Problem
The function
f
f
f
is continuous for
t
≥
0
t\ge 0
t
≥
0
and is given by
f
(
t
)
=
6
−
t
2
f(t)=6-t^{2}
f
(
t
)
=
6
−
t
2
. For which of the following values of
k
>
0
k>0
k
>
0
is the average value of
f
f
f
on
[
0
,
k
]
[0,k]
[
0
,
k
]
equal to
4
4
4
? a)
3
3
3
b)
6
\sqrt{6}
6
c)
12
\sqrt{12}
12
d)
2
\sqrt{2}
2
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