Mathematics

Mathematics

Problem

If y=23xy = 2^{3^x} , then y′y' equals a. 3x⋅log⁡3⋅log⁡23^x \cdot \log 3 \cdot \log 2 b. y⋅(log⁡2y)⋅log⁡3⋅log⁡2y \cdot (\log_2 y) \cdot \log 3 \cdot \log 2 c. 23x⋅3x⋅log⁡62^{3^x} \cdot 3^x \cdot \log 6 d. 23x⋅3x⋅log⁡3⋅log⁡22^{3^x} \cdot 3^x \cdot \log 3 \cdot \log 2

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