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Mathematics
Mathematics
Problem
Let
a
,
b
,
c
a, b, c
a
,
b
,
c
be the lengths of the sides of a triangle (no two of them are equal) and
k
∈
R
k \in R
k
∈
R
. If the roots of the equation
x
2
+
2
(
a
+
b
+
c
)
x
+
6
k
(
a
b
+
b
c
+
c
a
)
=
0
x^2 + 2(a + b + c)x + 6k(ab + bc + ca) = 0
x
2
+
2
(
a
+
b
+
c
)
x
+
6
k
(
ab
+
b
c
+
c
a
)
=
0
are real, then: (a)
k
<
2
3
k < \frac{2}{3}
k
<
3
2
(b)
k
>
2
3
k > \frac{2}{3}
k
>
3
2
(c)
k
>
1
k > 1
k
>
1
(d)
k
<
1
4
k < \frac{1}{4}
k
<
4
1
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