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Mathematics
Problem
Suppose
h
h
h
is differentiable at
x
=
2
x=2
x
=
2
with
h
(
2
)
=
3
h(2)=3
h
(
2
)
=
3
and
h
′
(
2
)
=
7
h'(2)=7
h
′
(
2
)
=
7
. What is
lim
x
→
2
h
(
x
)
−
3
x
−
2
\displaystyle \lim_{x\to 2}\frac{h(x)-3}{x-2}
x
→
2
lim
x
−
2
h
(
x
)
−
3
? a)
0
0
0
b)
7
7
7
c)
1
7
\dfrac{1}{7}
7
1
d) The limit does not exist
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