Introduction to Solid State Physics · Problem 3

PHONONS II. THERMAL PROPERTIES — Charles Kittel

Physics — Solid State · zero-point-lattice-displacement-and-strain

Problem

Zero point lattice displacement and strain. (a) In the Debye approximation, show that the mean square displacement of an atom at absolute zero is ⟨R2⟩=3ℏωD2/8π2ρv3\langle R^2 \rangle = 3\hbar\omega_D^2/8\pi^2\rho v^3, where vv is the velocity of sound. Start from the result (4.29) summed over the independent lattice modes: ⟨R2⟩=(ℏ/2ρV)Σω−1\langle R^2 \rangle = (\hbar/2\rho V)\Sigma\omega^{-1}. We have included a factor of 12\frac{1}{2} to go from mean square amplitude to mean square displacement. (b) Show that Σω−1\Sigma\omega^{-1} and ⟨R2⟩\langle R^2 \rangle diverge for a one-dimensional lattice, but that the mean square strain is finite. Consider ⟨(∂R/∂x)2⟩=12ΣK2u02\langle (\partial R/\partial x)^2 \rangle = \frac{1}{2}\Sigma K^2 u_0^2 as the mean square strain, and show that it is equal to ℏωD2L/4MNv3\hbar\omega_D^2 L/4MNv^3 for a line of NN atoms each of mass MM, counting longitudinal modes only. The divergence of R2R^2 is not significant for any physical measurement.

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