Prove: cos⁡(x−y)cos⁡(x+y)=1+tan⁡xtan⁡y1−tan⁡xtan⁡y\frac{\cos(x - y)}{\cos(x + y)} = \frac{1 + \tan x \tan y}{1 - \tan x \tan y}

Mathematics

Problem

Prove: cos⁡(x−y)cos⁡(x+y)=1+tan⁡xtan⁡y1−tan⁡xtan⁡y\frac{\cos(x - y)}{\cos(x + y)} = \frac{1 + \tan x \tan y}{1 - \tan x \tan y}

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