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Problem
Problem
Let
f
(
x
)
=
8
x
3
−
6
x
2
−
2
x
+
1
f(x) = 8x^3 - 6x^2 - 2x + 1
f
(
x
)
=
8
x
3
−
6
x
2
−
2
x
+
1
, then a.
f
(
x
)
=
0
f(x) = 0
f
(
x
)
=
0
has no root in
(
0
,
1
)
(0, 1)
(
0
,
1
)
b.
f
(
x
)
=
0
f(x) = 0
f
(
x
)
=
0
has atleast one root in
(
0
,
1
)
(0, 1)
(
0
,
1
)
c.
f
′
(
c
)
f'(c)
f
′
(
c
)
vanishes for some
c
∈
(
0
,
1
)
c \in (0, 1)
c
∈
(
0
,
1
)
d. None of the above
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