Physics

Physics

Problem

A deep-sea diver notes that the gauge on his pressure suit reads 2.19×105 Pa2.19 \times 10^{5}\,\text{Pa} at one depth, where the absolute pressure is 3.20×105 Pa3.20 \times 10^{5}\,\text{Pa}. He then descends until the gauge reads 4.90×105 Pa4.90 \times 10^{5}\,\text{Pa}. Assuming seawater density 1.03×103 kg m−31.03 \times 10^{3}\,\text{kg}\,\text{m}^{-3} and g=9.8 m s−2g = 9.8\,\text{m}\,\text{s}^{-2}, determine the additional depth through which he has descended. a) 49 m49\,\text{m} b) 21 m21\,\text{m} c) 27 m27\,\text{m} d) 39 m39\,\text{m}

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