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Chemistry
Chemistry
Problem
The half-reaction
Zn
2
+
(
a
q
)
+
2
e
−
→
Zn
(
s
)
\text{Zn}^{2+}(aq)+2e^- \rightarrow \text{Zn}(s)
Zn
2
+
(
a
q
)
+
2
e
−
→
Zn
(
s
)
has a standard potential of
E
∘
=
−
0.76
V
E^\circ=-0.76\;\text{V}
E
∘
=
−
0.76
V
at 298 K. Determine the standard Gibbs free energy change, in kJ per mole of Zn(s) formed, for this half-reaction. Use
F
=
9.65
×
10
4
C mol
−
1
F = 9.65\times10^4\;\text{C mol}^{-1}
F
=
9.65
×
1
0
4
C mol
−
1
.
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