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Mathematics
Mathematics
Problem
If
9
x
cos
θ
+
5
y
sin
θ
=
56
\frac{9x}{\cos \theta} + \frac{5y}{\sin \theta} = 56
c
o
s
θ
9
x
+
s
i
n
θ
5
y
=
56
and
9
x
sin
θ
cos
2
θ
−
5
y
cos
θ
sin
2
θ
=
0
\frac{9x \sin \theta}{\cos^2 \theta} - \frac{5y \cos \theta}{\sin^2 \theta} = 0
c
o
s
2
θ
9
x
s
i
n
θ
−
s
i
n
2
θ
5
y
c
o
s
θ
=
0
then the value of
[
(
9
x
)
2
+
(
5
y
)
2
]
3
\left[ (9x)^2 + (5y)^2 \right]^3
[
(
9
x
)
2
+
(
5
y
)
2
]
3
is
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