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Mathematics
Problem
Find the value of
k
k
k
so that the function
f
(
x
)
=
{
k
x
2
+
3
x
,
x
<
2
,
5
x
−
k
,
x
≥
2
f(x)=\begin{cases} kx^{2}+3x,& x<2,\\ 5x-k,& x\ge 2 \end{cases}
f
(
x
)
=
{
k
x
2
+
3
x
,
5
x
−
k
,
x
<
2
,
x
≥
2
is continuous at
x
=
2
x=2
x
=
2
.
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