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Mathematics
Mathematics
Problem
Solve
sin
2
θ
=
1
2
\sin 2\theta = \dfrac{1}{2}
sin
2
θ
=
2
1
for
θ
\theta
θ
in the interval
0
∘
≤
θ
<
360
∘
0^{\circ} \le \theta < 360^{\circ}
0
∘
≤
θ
<
36
0
∘
.
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