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Physics
Physics
Problem
The potential energy of a particle moving along the
x
x
x
-axis is given by
V
(
x
)
=
2
x
3
−
6
x
V(x)=2x^{3}-6x
V
(
x
)
=
2
x
3
−
6
x
(in joules,
x
x
x
in metres). Determine the direction of the force acting on the particle at: a. (i)
x
=
−
1
m
x = -1\,\text{m}
x
=
−
1
m
b. (ii)
x
=
+
1
m
x = +1\,\text{m}
x
=
+
1
m
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