Physics

Physics

Problem

The potential energy of a particle moving along the xx-axis is given by V(x)=2x3−6xV(x)=2x^{3}-6x (in joules, xx in metres). Determine the direction of the force acting on the particle at: a. (i) x=−1 mx = -1\,\text{m} b. (ii) x=+1 mx = +1\,\text{m}

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