Classical Electrodynamics · Problem 14.10

Radiating Systems, Multipole Fields and Radiation — John David Jackson

Physics — E&M · radiation-sudden-deceleration

Problem

A particle of charge ee moves at constant velocity βc\boldsymbol{\beta}c for t<0t < 0. During the short time interval, 0<t<Δt0 < t < \Delta t, its velocity remains in the same direction, but its speed decreases linearly in time to zero. For t>Δtt > \Delta t, the particle remains at rest. (a) Show that the radiant energy emitted per unit solid angle is dEdΩ=e2β216πc Δt(2−βcos⁡θ)[1+(1−βcos⁡θ)2]sin⁡2θ(1−βcos⁡θ)4\frac{dE}{d\Omega} = \frac{e^2 \beta^2}{16\pi c\, \Delta t} \frac{(2 - \beta\cos\theta)[1 + (1 - \beta\cos\theta)^2]\sin^2\theta}{(1 - \beta\cos\theta)^4} where θ\theta is the polar angle relative to the direction of the initial velocity. (b) In the limit of γ≫1\gamma \gg 1, show that the angular distribution can be expressed as dEdξ≈e2β2γ4c Δtξ(1+ξ)4\frac{dE}{d\xi} \approx \frac{e^2 \beta^2 \gamma^4}{c\, \Delta t} \frac{\xi}{(1 + \xi)^4} where ξ=(γθ)2\xi = (\gamma\theta)^2. Show that ⟨θ2⟩1/2≈2/γ\langle\theta^2\rangle^{1/2} \approx \sqrt{2}/\gamma and that the expression for the total energy radiated is in agreement with the result from (14.43) in the same limit.

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