Griffiths Introduction to Elementary Particles · Problem 3.13

Symmetries — David J. Griffiths

Physics — QFT · relativistic-kinematics-decay

Problem

A pion traveling at speed vv decays into a muon and a neutrino, π→μ+ν\pi \to \mu + \nu. If the neutrino emerges at 90° to the original pion direction, at what angle does the μ\mu come off? [AnswerAnswer: tan⁡θ=(1−mμ2/mπ2)/(2βγ2)\tan\theta = (1 - m_\mu^2/m_\pi^2)/(2\beta\gamma^2)]

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