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Mathematics
Mathematics
Problem
If
z
+
1
z
=
1
z + \frac{1}{z} = 1
z
+
z
1
=
1
and
a
=
z
2017
+
1
z
2017
a = z^{2017} + \frac{1}{z^{2017}}
a
=
z
2017
+
z
2017
1
and
b
b
b
is the last digit of the number
2
2
n
−
1
2^{2^n} - 1
2
2
n
−
1
, when the integer
n
>
1
n > 1
n
>
1
, the value of
a
2
+
b
2
a^2 + b^2
a
2
+
b
2
is a. 23 b. 24 c. 26 d. 27
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