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Mathematics
Mathematics
Problem
∫
(
3
cosec
2
x
+
2
sin
3
x
)
d
x
=
\int (3\operatorname{cosec}^2 x + 2\sin 3x)\,dx =
∫
(
3
cosec
2
x
+
2
sin
3
x
)
d
x
=
(a)
3
cot
x
+
2
3
cos
3
x
+
c
3\cot x + \frac{2}{3}\cos 3x + c
3
cot
x
+
3
2
cos
3
x
+
c
(b)
−
(
3
cot
x
+
2
3
cos
3
x
)
+
c
-\left(3\cot x + \frac{2}{3}\cos 3x\right) + c
−
(
3
cot
x
+
3
2
cos
3
x
)
+
c
(c)
3
cot
x
−
2
3
cos
3
x
+
c
3\cot x - \frac{2}{3}\cos 3x + c
3
cot
x
−
3
2
cos
3
x
+
c
(d) None of these (a)
3
cot
x
+
2
3
cos
3
x
+
c
3\cot x + \frac{2}{3}\cos 3x + c
3
cot
x
+
3
2
cos
3
x
+
c
(b)
−
(
3
cot
x
+
2
3
cos
3
x
)
+
c
-\left(3\cot x + \frac{2}{3}\cos 3x\right) + c
−
(
3
cot
x
+
3
2
cos
3
x
)
+
c
(c)
3
cot
x
−
2
3
cos
3
x
+
c
3\cot x - \frac{2}{3}\cos 3x + c
3
cot
x
−
3
2
cos
3
x
+
c
(d) None of these
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