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Chemistry
Chemistry
Problem
Calculate the molar solubility of
SrF
2
\text{SrF}_2
SrF
2
in a
0.020
M
0.020\,\text{M}
0.020
M
NaF solution at 25 °C. The solubility–product constant is
K
s
p
=
4.2
×
10
−
9
K_{sp}=4.2\times10^{-9}
K
s
p
=
4.2
×
1
0
−
9
. a)
3.2
×
10
−
3
M
3.2\times10^{-3}\,\text{M}
3.2
×
1
0
−
3
M
b)
1.1
×
10
−
5
M
1.1\times10^{-5}\,\text{M}
1.1
×
1
0
−
5
M
c)
2.1
×
10
−
7
M
2.1\times10^{-7}\,\text{M}
2.1
×
1
0
−
7
M
d)
1.0
×
10
−
4
M
1.0\times10^{-4}\,\text{M}
1.0
×
1
0
−
4
M
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