Physics

Physics

Problem

A simple pendulum of length L=2.5 mL = 2.5\,\text{m} is displaced by a small angle. As it passes through the mean position, its velocity is measured to be vmax=0.5 m/sv_{\text{max}} = 0.5\,\text{m/s}. Determine the amplitude of oscillation (in meters). Take g=10 m/s2g = 10\,\text{m/s}^{2}.

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