Mathematics

Mathematics

Problem

If the straight lines x−12=y+1k=z2\frac{x-1}{2} = \frac{y+1}{k} = \frac{z}{2} and x+15=y+12=zk\frac{x+1}{5} = \frac{y+1}{2} = \frac{z}{k} are coplanar, then the plane(s) containing these two lines is/are a. y+2z=−1y + 2z = -1 b. y+z=−1y + z = -1 c. y−z=−1y - z = -1 d. y−2z=−1y - 2z = -1

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