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Mathematics
Mathematics
Problem
Prove that
(
sec
θ
−
tan
θ
)
(
sec
θ
+
tan
θ
)
=
1
(\sec\theta-\tan\theta)(\sec\theta+\tan\theta)=1
(
sec
θ
−
tan
θ
)
(
sec
θ
+
tan
θ
)
=
1
for an acute angle
θ
\theta
θ
.
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