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Chemistry
Chemistry
Problem
If
E
A
1
EA_1
E
A
1
and
E
A
2
EA_2
E
A
2
for oxygen atom are
−
142
kJ mol
−
1
-142\ \text{kJ mol}^{-1}
−
142
kJ mol
−
1
and
+
844
kJ mol
−
1
+844\ \text{kJ mol}^{-1}
+
844
kJ mol
−
1
. The energy released to form
2
O
+
2
e
⟶
2
O
−
2\text{O} + 2e \longrightarrow 2\text{O}^-
2
O
+
2
e
⟶
2
O
−
will be: (in
kJ mol
−
1
\text{kJ mol}^{-1}
kJ mol
−
1
) a. 986 b. 702 c. 284 d. 1688
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