(x−1)(x+1)(x+4)(x+6)7x2+8x+4>0\frac{(x-1)(x+1)(x+4)(x+6)}{7x^2+8x+4} > 0

Problem

(x−1)(x+1)(x+4)(x+6)7x2+8x+4>0\frac{(x-1)(x+1)(x+4)(x+6)}{7x^2+8x+4} > 0

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