Problem

Problem

# Short-answer questions a. State Newton's universal law of gravitation. b. Show that the gravitational potential energy of a body of mass mm , at the surface of the Earth, of radius RR , and mass MM , is given by the expression EP=−GMmR.E_P = -G \frac{Mm}{R} . c. Hence, show that the gravitational potential at the Earth's surface is 62.5 MJ kg−162.5 \text{ MJ kg}^{-1} . ( MEarth=6×1024M_{\text{Earth}} = 6 \times 10^{24} , R=6.4×106 mR = 6.4 \times 10^6 \text{ m} , G=6.67×10−11 N m2 kg−2G = 6.67 \times 10^{-11} \text{ N m}^2 \text{ kg}^{-2} )

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