Abstract Algebra: Theory and Applications · Problem 11.4.9

Matrix Groups and Symmetry — Thomas Judson

Mathematics — Abstract Algebra · homomorphic-image-abelian

Problem

If ϕ:G→H\phi : G \to H is a group homomorphism and GG is abelian, prove that ϕ(G)\phi(G) is also abelian. Hint. Let a,b∈Ga, b \in G. Then ϕ(a)ϕ(b)=ϕ(ab)=ϕ(ba)=ϕ(b)ϕ(a)\phi(a)\phi(b) = \phi(ab) = \phi(ba) = \phi(b)\phi(a).

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