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Mathematics
Mathematics
Problem
Show that
sin
θ
sec
(
90
∘
−
θ
)
+
cos
θ
csc
(
90
∘
−
θ
)
=
2
\sin \theta\; \sec(90^{\circ} - \theta) + \cos \theta\; \csc(90^{\circ} - \theta) = 2
sin
θ
sec
(
9
0
∘
−
θ
)
+
cos
θ
csc
(
9
0
∘
−
θ
)
=
2
for any acute angle
θ
\theta
θ
.
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