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Problem
Problem
Find
tan
θ
\tan \theta
tan
θ
exactly given: a.
sin
θ
=
1
3
\sin \theta = \frac{1}{3}
sin
θ
=
3
1
and
π
2
<
θ
<
π
\frac{\pi}{2} < \theta < \pi
2
π
<
θ
<
π
b.
cos
θ
=
1
5
\cos \theta = \frac{1}{5}
cos
θ
=
5
1
and
3
π
2
<
θ
<
2
π
\frac{3\pi}{2} < \theta < 2\pi
2
3
π
<
θ
<
2
π
c.
sin
θ
=
−
1
3
\sin \theta = -\frac{1}{\sqrt{3}}
sin
θ
=
−
3
1
and
π
<
θ
<
3
π
2
\pi < \theta < \frac{3\pi}{2}
π
<
θ
<
2
3
π
d.
cos
θ
=
−
3
4
\cos \theta = -\frac{3}{4}
cos
θ
=
−
4
3
and
π
2
<
θ
<
π
\frac{\pi}{2} < \theta < \pi
2
π
<
θ
<
π
.
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