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Abstract Algebra: Theory and Applications
· Problem 2.4.31
Groups — Thomas Judson
Mathematics — Abstract Algebra · sqrt-2-irrational
Problem
Using the fact that 2 is prime, show that there do not exist integers
p
p
p
and
q
q
q
such that
p
2
=
2
q
2
p^2 = 2q^2
p
2
=
2
q
2
. Demonstrate that therefore
2
\sqrt{2}
2
cannot be a rational number.
Related theory
2 As An Irrational Number
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