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Mathematics
Mathematics
Problem
Prove the following identity for
0
∘
<
θ
<
90
∘
0^\circ<\theta<90^\circ
0
∘
<
θ
<
9
0
∘
. a.
1
−
cos
θ
sin
θ
=
sin
θ
1
+
cos
θ
\dfrac{1-\cos\theta}{\sin\theta}=\dfrac{\sin\theta}{1+\cos\theta}
sin
θ
1
−
cos
θ
=
1
+
cos
θ
sin
θ
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