Physics

Physics · thermodynamics

Problem

iii. The dropper's functioning can be hindered by the effect shown in Part A-iii. In addition, a limit Umax⁡U_{\max } to the achievable potential between the electrodes is set by the electrostatic push between a droplet and the bowl beneath it. Find Umax U_{\text {max }}. Given constants: Problem T2. Kelvin water dropper The following facts about the surface tension may turn out to be useful for this problem. For the molecules of a liquid, the positions at the liquid-air interface are less favourable as compared with the positions in the bulk of the liquid. This interface is described by the so-called surface energy, U=σSU=\sigma S, where SS is the surface area of the interface and σ\sigma is the surface tension coefficient of the liquid. Moreover, two fragments of the liquid surface pull each other with a force F=σlF=\sigma l, where ll is the length of a straight line separating the fragments. <image_1> A long metallic pipe with internal diameter dd is pointing directly downwards. Water is slowly dripping from a nozzle at its lower end, see fig. Water can be considered to be electrically conducting; its surface tension is σ\sigma and its density is ρ\rho. A droplet of radius rr hangs below the nozzle. The radius grows slowly in time until the droplet separates from the nozzle due to the free fall acceleration gg. Always assume that d≪rd \ll r. Part A. Single pipe Context question: i. Find the radius rmax⁡r_{\max } of a drop just before it separates from the nozzle. Context answer: rmax⁡=3σd4ρg3r_{\max }=\sqrt[3]{\frac{3 \sigma d}{4 \rho g}} Context question: ii. Relative to the far-away surroundings, the pipe's electrostatic potential is φ\varphi. Find the charge QQ of a drop when its radius is rr. Context answer: Q=4πε0φrQ=4 \pi \varepsilon_{0} \varphi r Context question: iii. Consider the situation in which rr is kept constant and φ\varphi is slowly increased. The droplet becomes unstable and breaks into pieces if the hydrostatic pressure inside the droplet becomes smaller than the atmospheric pressure. Find the critical potential φmax⁡\varphi_{\max } at which this will happen. Context answer: φmax⁡=2σrε0\varphi_{\max }=2 \sqrt{\frac{\sigma r}{ \varepsilon_{0}}} Extra Supplementary Reading Materials: Part B. Two pipes An apparatus called the "Kelvin water dropper" consists of two pipes, each identical to the one described in Part A, connected via a T-junction, see fig. The ends of both pipes are at the centres of two cylindrical electrodes (with height LL and diameter DD with L≫D≫rL \gg D \gg r ). For both tubes, the dripping rate is nn droplets per unit time. Droplets fall from height HH into conductive bowls underneath the nozzles, cross-connected to the electrodes as shown in the diagram. The electrodes are connected via a capacitance CC. There is no net charge on the system of bowls and electrodes. Note that the top water container is earthed as shown. The first droplet to fall will have some microscopic charge which will cause an imbalance between the two sides and a small charge separation across the capacitor. <image_2> Context question: i. Express the absolute value of the charge Q0Q_{0} of the drops as they separate from the tubes, and at the instant when the capacitor's charge is qq. Express Q0Q_{0} in terms of rmax⁡r_{\max } (from Part A-i) and neglect the effect described in Part A-iii. Context answer: Q0=2πε0qrmax⁡/CQ_{0}=2 \pi \varepsilon_{0} q r_{\max } / C Context question: ii. Find the dependence of qq on time tt by approximating it with a continuous function q(t)q(t) and assuming that q(0)=q0q(0)=q_{0}. Context answer: q(t)=q0eγtq(t)=q_{0} e^{\gamma t} , γ=πε0nC6σdρg3\gamma=\frac{\pi \varepsilon_{0} n}{C} \sqrt[3]{\frac{6 \sigma d}{\rho g}}

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