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›
Problems
Let
f
(
x
)
=
∣
2
cos
x
1
0
1
2
cos
x
1
0
1
2
cos
x
∣
f(x) = \begin{vmatrix} 2 \cos x & 1 & 0 \\ 1 & 2 \cos x & 1 \\ 0 & 1 & 2 \cos x \end{vmatrix}
f
(
x
)
=
2
cos
x
1
0
1
2
cos
x
1
0
1
2
cos
x
…
Mathematics
Problem
Let
f
(
x
)
=
∣
2
cos
x
1
0
1
2
cos
x
1
0
1
2
cos
x
∣
f(x) = \begin{vmatrix} 2 \cos x & 1 & 0 \\ 1 & 2 \cos x & 1 \\ 0 & 1 & 2 \cos x \end{vmatrix}
f
(
x
)
=
2
cos
x
1
0
1
2
cos
x
1
0
1
2
cos
x
, then a.
f
(
π
3
)
=
−
1
f\left(\frac{\pi}{3}\right) = -1
f
(
3
π
)
=
−
1
b.
f
(
π
3
)
=
3
f\left(\frac{\pi}{3}\right) = \sqrt{3}
f
(
3
π
)
=
3
c.
∫
0
π
f
(
x
)
d
x
=
0
\int_{0}^{\pi} f(x) dx = 0
∫
0
π
f
(
x
)
d
x
=
0
d.
∫
−
π
π
f
(
x
)
d
x
=
0
\int_{-\pi}^{\pi} f(x) dx = 0
∫
−
π
π
f
(
x
)
d
x
=
0
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