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Problem
Problem
Solve the inequation
log
(
x
−
3
)
(
2
(
x
2
−
10
x
+
24
)
)
≥
log
(
x
−
3
)
(
x
2
−
9
)
.
\log_{(x-3)}(2(x^2 - 10x + 24)) \ge \log_{(x-3)}(x^2 - 9).
lo
g
(
x
−
3
)
(
2
(
x
2
−
10
x
+
24
))
≥
lo
g
(
x
−
3
)
(
x
2
−
9
)
.
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