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Mathematics
Problem
The trajectory of projectile, projected from the ground is given by
y
=
x
−
x
2
20
y = x - \frac{x^2}{20}
y
=
x
−
20
x
2
, where
x
x
x
and
y
y
y
are measured in metre. The maximum height attained by the projectile will be (a) 200 m (b) 5 m (c) 10 m (d)
10
2
10\sqrt{2}
10
2
m
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