Mathematics

Mathematics

Problem

Two circles x2+y2=6x^2 + y^2 = 6 and x2+y2−6x+8=0x^2 + y^2 - 6x + 8 = 0 are given. Then, the equation of the circle through their points of intersection and the point (1,1)(1, 1) is a. x2+y2−6x+4=0x^2 + y^2 - 6x + 4 = 0 b. x2+y2−3x+1=0x^2 + y^2 - 3x + 1 = 0 c. x2+y2−4x+2=0x^2 + y^2 - 4x + 2 = 0 d. x2+y2−2x+1=0x^2 + y^2 - 2x + 1 = 0

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