Mathematics

Mathematics

Problem

For a curve defined by x=f(t)x=f(t) and y=g(t)y=g(t), the following values are known at t=2t=2: dxdt=−4,ddt ⁣(dydx)=6.\frac{dx}{dt}=-4, \qquad \frac{d}{dt}\!\left(\frac{dy}{dx}\right)=6. Which statement correctly describes the concavity of the curve at the corresponding point? a) The concavity cannot be determined because dy/dxdy/dx at t=2t=2 is unknown. b) The curve is concave down because ddt(dydx)dxdt<0\displaystyle \frac{\frac{d}{dt}\left(\frac{dy}{dx}\right)}{\frac{dx}{dt}}<0. c) The curve is concave up because ddt(dydx)\dfrac{d}{dt}\bigl(\frac{dy}{dx}\bigr) is positive. d) The curve is concave up because both given derivatives are non–zero.

Browse the problem library