If the vertices of ΔABC are A(cosα,sinα), B(cosβ,sinβ) and C(cosγ,sinγ), then the orthocentre of the triangle is
(1) ((cosα+cosβ+cosγ),(sinα+sinβ+sinγ))
(2) ((cosα+cosβ+cosγ),2(sinα+sinβ+sinγ))
(3) (0, 0)
(4) ((2cosα+2cosβ+2cosγ),(2sinβ+2sinγ+2sinα))