If lim⁡n→∞n⋅3nn(x−2)n−n⋅3n+1−3n=13\lim_{n \to \infty} \frac{n \cdot 3^n}{n(x-2)^n - n \cdot 3^{n+1} - 3^n} = \frac{1}{3}…

Problem

If lim⁡n→∞n⋅3nn(x−2)n−n⋅3n+1−3n=13\lim_{n \to \infty} \frac{n \cdot 3^n}{n(x-2)^n - n \cdot 3^{n+1} - 3^n} = \frac{1}{3} , where n∈Nn \in \mathbb{N} , the number of integer(s) in the range of ' xx ' is a. 3 b. 4 c. 5 d. infinite

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