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Problem
Problem
In a
Δ
A
B
C
\Delta ABC
Δ
A
B
C
,
tan
1
2
(
A
+
B
)
⋅
cot
1
2
(
A
−
B
)
\tan \frac{1}{2}(A + B) \cdot \cot \frac{1}{2}(A - B)
tan
2
1
(
A
+
B
)
⋅
cot
2
1
(
A
−
B
)
is equal to a.
a
−
b
a
+
b
\frac{a-b}{a+b}
a
+
b
a
−
b
b.
a
+
b
c
\frac{a+b}{c}
c
a
+
b
c.
a
+
b
a
−
b
\frac{a+b}{a-b}
a
−
b
a
+
b
d.
a
−
b
2
(
a
+
b
)
\frac{a-b}{2(a+b)}
2
(
a
+
b
)
a
−
b
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