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Mathematics
Problem
(
1
−
a
)
+
3
(
1
−
a
)
2
=
0
(1-a) + 3(1-a)^2 = 0
(
1
−
a
)
+
3
(
1
−
a
)
2
=
0
What are the solutions to the equation above? A.
a
=
1
a = 1
a
=
1
B.
a
=
4
3
a = \frac{4}{3}
a
=
3
4
C.
a
=
1
a = 1
a
=
1
and
a
=
4
3
a = \frac{4}{3}
a
=
3
4
D.
a
=
0
a = 0
a
=
0
and
a
=
−
1
3
a = -\frac{1}{3}
a
=
−
3
1
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