Physics

Problem

A proton (

m = 1.67 \times 10^{-27}\,\text{kg}

q = 1.6 \times 10^{-19}\,\text{C}

) enters a uniform magnetic field of magnitude

0.20\,\text{T}

with a speed of

4.0 \times 10^{6}\,\text{m\,s}^{-1}

, the velocity being perpendicular to the field. Determine the radius of the circular path followed by the proton. a)

2.1\,\text{m}

0.21\,\text{m}

0.104\,\text{m}

0.021\,\text{m}