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Mathematics
Mathematics
Problem
Let
l
1
=
∫
0
1
e
x
1
+
x
d
x
l_1 = \int_{0}^{1} \frac{e^x}{1+x} dx
l
1
=
∫
0
1
1
+
x
e
x
d
x
and
l
2
=
∫
0
1
x
2
e
x
3
(
2
−
x
3
)
d
x
l_2 = \int_{0}^{1} \frac{x^2}{e^{x^3}(2-x^3)} dx
l
2
=
∫
0
1
e
x
3
(
2
−
x
3
)
x
2
d
x
. Then
l
1
l
2
\frac{l_1}{l_2}
l
2
l
1
is equal to a.
3
e
\frac{3}{e}
e
3
b.
3
e
2
\frac{3}{e^2}
e
2
3
c.
3
e
3e
3
e
d.
1
3
e
\frac{1}{3e}
3
e
1
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