Physics

Problem

16. A newly discovered planet has twice the mass of the Earth, but the acceleration due to gravity on the new planet's surface is exactly the same as the acceleration due to gravity on the Earth's surface. The radius of the new planet in terms of the radius R of Earth is (A)

1 / 2 \mathrm{R}

(B)

\frac{\sqrt{2}}{2} \mathrm{R}

(C)

\sqrt{2} \mathrm{R}

(D)

2 R

(A)

1 / 2 \mathrm{R}

(B)

\frac{\sqrt{2}}{2} \mathrm{R}

(C)

\sqrt{2} \mathrm{R}

(D)

2 R

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